每日签单实现

简单每日签到实现

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签到如YII官方的一样

直接php代码 当然还需要结合ajax和jq(不贴了)

if(IS_AJAX){
        $userid = $_SESSION['username']['id'];
        $sign_model = D('sign');
        $detail_model = D('user_detail');
        $where = array('userid'=>$userid);
        $time = date('Y-m-d',time());
        $now_time = strtotime($time);
        $time_where = array('signtime'=>$now_time);
        //判断是否为第一次签到
        $res = $sign_model->where($where)->find();
        //用户积分情况
        $details = $detail_model->where($where)->find();
        if(empty($res)){
            //第一次签到新增签到表
            $data['cta'] =  1;
            $data['num'] =  1;
            $data['signtime'] = $now_time;
            $data['userid'] = $userid;
            $sign_model->add($data);
            $details['integral'] += 5;
            $detail_model->save($details);
            //返回连续签到天数
            $arr =  array(
                'status'=>'ok',
                'cta'=>1
                );

        }else{
            //已经签到
            if($res['signtime']==$now_time){
                exit(json_encode(array('status'=>'happened')));
                die;
            }
            //断签
            if(($now_time-$res['signtime'])>24*3600){
                $res['cta'] = 1;
            }else{
            //连续签到
                $res['cta'] += 1;
            }
            $res['signtime'] = $now_time;
            $res['num'] +=  1;
            $sign_model->save($res);
            //用户连续签到7天
            if($res['cta']%7==0){
                $details['integral'] += 20;
            }else{
                $details['integral'] += 5;
            }
            //返回连续签到天数
            $arr =  array(
                'status'=>'ok',
                'cta'=>$res['cta'],
                );
        }

        $detail_model->save($details);
        //更新今日有多少人签到
        $query = $sign_model->field('sign_id')->where($time_where)->select();
        $count = count($query);
        //签到总人数
        $arr = array_merge($arr,array('count'=>$count));
        exit(json_encode($arr));
    }